3x^2+2x+21/4x-21/4=0

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Solution for 3x^2+2x+21/4x-21/4=0 equation: 


x in (-oo:+oo)

3*x^2+2*x+(21/4)*x-(21/4) = 0

3*x^2+2*x+(21/4)*x-21/4 = 0

3*x^2+29/4*x-21/4 = 0

DELTA = (29/4)^2-(-21/4*3*4)

DELTA = 1849/16

DELTA > 0

x = ((1849/16)^(1/2)-29/4)/(2*3) or x = (-(1849/16)^(1/2)-29/4)/(2*3)

x = 7/12 or x = -3

x in { -3, 7/12 }

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